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Projected order of finish in the Presidential race

At this point, enough votes are in to project (wth a pretty high level of certainty) that the order of finish in the Presidential election will be as follows…

1 – Barack Obama
2 – John McCain
3 – Ralph Nader (ind)
4 – Bob Barr (lib)
5 – Cynthia McKinney (grn)
6 – Chuck Baldwin (con)
7 – Alan Keyes (aip)

Those are the seven candidates who have or appear likely to surpass 100,000 votes each.

Ron Paul will likely come in 8th, followed by a wide field of Socialists and other smaller parties.

5 Comments

  1. paulie cannoli November 5, 2008

    With 90% counted

    Ralph Nader, 611,125 3rd

    Bob Barr, 460,619 4th

    Chuck Baldwin, 167,795 5th

    Cynthia McKinney, 128,153 6th

    Alan Keyes, AIP 26,001

    Ron Paul, CST 17,812

    Paul and Baldwin are best positioned to benefit from write-in votes, especially in California.

    There is thus a decent chance Ron Paul will have more than Keyes in the end.

    Doesn’t look like much chance of McKinney passing Baldwin at this point.

  2. rdupuy November 5, 2008

    Sounds like a large number for McKinney in CA. She may do only 30,000.

    However I admit I, at first, also thought McKinney might top Baldwin due to Ca.

  3. Austin Cassidy Post author | November 5, 2008

    Looks like McKinney could do 55,000 or a little better in CA. Baldwin might get 5,000-10,000 write-in votes. Maybe.

  4. Austin Cassidy Post author | November 5, 2008

    Baldwin isn’t on the ballot in California though.

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